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Physical & Chemical properties

Vapour pressure

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Reference
Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
20 December 2018 to 07 January 2019
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
guideline study
Qualifier:
according to guideline
Guideline:
OECD Guideline 104 (Vapour Pressure Curve)
Deviations:
no
Qualifier:
according to guideline
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
GLP compliance:
yes (incl. QA statement)
Remarks:
Date of Inspection: 21 August 2018 Date of Issue: 19 November 2018
Type of method:
effusion method: vapour pressure balance
Key result
Temp.:
25 °C
Vapour pressure:
0.002 Pa

Recorded temperatures, mass differences, and the resulting calculated values of vapour pressure are shown in the following tables:

Run 6

Table 1 - Vapour Pressure Data

Temperature (°C)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

20

293.15

0.003411

1.06

1.060e-09

0.00147

-2.83268

21

294.15

0.003400

1.20

1.200e-09

0.00167

-2.77728

22

295.15

0.003388

0.73

7.300e-10

0.00101

-2.99568

23

296.15

0.003377

1.36

1.360e-09

0.00189

-2.72354

24

297.15

0.003365

1.68

1.680e-09

0.00233

-2.63264

25

298.15

0.003354

1.47

1.470e-09

0.00204

-2.69037

26

299.15

0.003343

2.14

2.140e-09

0.00297

-2.52724

27

300.15

0.003332

2.03

2.030e-09

0.00282

-2.54975

28

301.15

0.003321

1.30

1.300e-09

0.00180

-2.74473

29

302.15

0.003310

1.16

1.160e-09

0.00161

-2.79317

30

303.15

0.003299

2.21

2.210e-09

0.00307

-2.51286

A plot of Log10 (Vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighed least squares treatment.

Slope: -2230

Standard error in slope: 1080

Intercept: 4.78

Standard error in intercept: 3.62

The results obtained indicate the following vapour pressure relationship:

Log10(Vp(Pa)) = [-2230/temp(K)] + 4.78

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of -2.71.

Run 7

Table 2 - Vapour Pressure Data

Temperature (°C)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

20

293.15

0.003411

0.78

7.800e-10

0.00108

-2.96658

21

294.15

0.003400

0.56

5.600e-10

0.00078

-3.10791

22

295.15

0.003388

1.03

1.030e-09

0.00143

-2.84466

23

296.15

0.003377

1.18

1.180e-09

0.00164

-2.78516

24

297.15

0.003365

1.99

1.990e-09

0.00276

-2.55909

25

298.15

0.003354

1.16

1.160e-09

0.00161

-2.79317

26

299.15

0.003343

1.34

1.340e-09

0.00186

-2.73049

27

300.15

0.003332

1.07

1.070e-09

0.00149

-2.82681

28

301.15

0.003321

1.43

1.430e-09

0.00199

-2.70115

29

302.15

0.003310

2.35

2.350e-09

0.00326

-2.48678

30

303.15

0.003299

1.71

1.710e-09

0.00237

-2.62525

A plot of Log10 (Vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 7 gives the following statistical data using an unweighed least squares treatment.

Slope: -3560

Standard error in slope: 1060

Intercept: 9.18

Standard error in intercept: 3.55

The results obtained indicate the following vapour pressure relationship:

Log10(Vp(Pa)) = [-3560/temp(K)] + 9.18

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of -2.76.

Run 8

Table 3 - Vapour Pressure Data

Temperature (°C)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

20

293.15

0.003411

1.05

1.050e-09

0.00146

-2.83565

21

294.15

0.003400

0.80

8.000e-10

0.00111

-2.95468

22

295.15

0.003388

0.68

6.800e-10

0.00094

-3.02687

23

296.15

0.003377

1.06

1.060e-09

0.00147

-2.83268

24

297.15

0.003365

1.01

1.010e-09

0.00140

-2.85387

25

298.15

0.003354

0.77

7.700e-10

0.00107

-2.97062

26

299.15

0.003343

1.85

1.850e-09

0.00257

-2.59007

27

300.15

0.003332

2.28

2.280e-09

0.00317

-2.49894

28

301.15

0.003321

2.05

2.050e-09

0.00285

-2.54516

29

302.15

0.003310

1.99

1.990e-09

0.00276

-2.55909

30

303.15

0.003299

1.73

1.730e-09

0.00240

-2.61979

A plot of Log10 (Vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 8 gives the following statistical data using an unweighed least squares treatment.

Slope: -4080

Standard error in slope: 1008

Intercept: 10.9

Standard error in intercept: 3.64

The results obtained indicate the following vapour pressure relationship:

Log10(Vp(Pa)) = [-4080/temp(K)] + 10.9

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of -2.75.

Run 10

Table 4 - Vapour Pressure Data

Temperature (°C)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

20

293.15

0.003411

0.43

4.300e-10

0.00060

-3.22185

21

294.15

0.003400

0.71

7.100e-10

0.00099

-3.00436

22

295.15

0.003388

0.90

9.000e-10

0.00125

-2.90309

23

296.15

0.003377

0.97

9.700e-10

0.00135

-2.86967

24

297.15

0.003365

1.40

1.400e-09

0.00194

-2.71220

25

298.15

0.003354

1.50

1.500e-09

0.00208

-2.68194

26

299.15

0.003343

1.13

1.130e-09

0.00157

-2.80410

27

300.15

0.003332

2.10

2.100e-09

0.00292

-2.53462

28

301.15

0.003321

1.95

1.950e-09

0.00271

-2.56703

29

302.15

0.003310

2.07

2.070e-09

0.00287

-2.54212

30

303.15

0.003299

1.63

1.630e-09

0.00226

-2.64589

A plot of Log10 (Vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 10 gives the following statistical data using an unweighed least squares treatment.

Slope: -5140

Standard error in slope: 886

Intercept: 14.5

Standard error in intercept: 2.97

The results obtained indicate the following vapour pressure relationship:

Log10(Vp(Pa)) = [-5140/temp(K)] + 14.5

The above yields a vapour pressure (Pa) at 298.15K with a common logarithm of -2.77.

The values of vapour presure at 25°C, extrapolated from each graph, are summarised in the following table:

Table 5 Summary of Vapour Pressure Data

Run

Log10[Vp(25°C)]

6

-2.71

7

-2.76

8

-2.75

10

-2.77

Mean

-2.75

Vapour Pressure

0.00179 Pa

The test item did not change in appearance under the conditions used in the determination.

A total of 10 runs were completed for the main sequence. Equilibrium with regard to vapour pressure has been assessed to have been reached over the final 4 runs (run 9 was not used due to a highly erroneous plot being obtained); thus the final 4 runs have been used to calculate the vapour pressure. The reported runs are on the limits of accuracy with regard to the mass difference obtained, any further runs on the sample would led to a less accurate limit value being imposed on the data.

The results may represent rounded values obtained by calculations based on the exact raw data.

Conclusions:
The vapour pressure of the test item has been determined to be 0.00179 Pa at 25°C.
Executive summary:

The vapour pressure of the test item has been determined to be 0.00179 Pa at 25°C, using the vapour pressure balance method, designed to be compatible with Method A.4 Vapour Pressure of Commission Regulation (EC) No 440/2008 of 30 May 2008 and Method 104 of the OECD Guidelines for Testing of Chemicals, 23 March 2006.

Description of key information

0.00179 Pa at 25°C; OECD 104; Ford, A.J. (2019)

Key value for chemical safety assessment

Vapour pressure:
0.002 Pa
at the temperature of:
25 °C

Additional information