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Administrative data

Endpoint:
vapour pressure
Type of information:
experimental study
Adequacy of study:
key study
Study period:
Testing was conducted between 05 January 2009 and 15 January 2009.anuary 2009 and 15 January 2009.
Reliability:
1 (reliable without restriction)
Rationale for reliability incl. deficiencies:
other: Study conducted in compliance with agreed protocols, with no or minor deviations from standard test guidelines and/or minor methodological deficiencies, which do not affect the quality of relevant results.

Data source

Reference
Reference Type:
study report
Title:
Unnamed
Year:
2009
Report date:
2009

Materials and methods

Test guideline
Qualifier:
according to guideline
Guideline:
EU Method A.4 (Vapour Pressure)
Deviations:
no
GLP compliance:
yes (incl. QA statement)
Remarks:
(Schedule 1, Good Laboratory Practice Regulations 1999 (SI 1999/3106 as amended by SI 2004/0994)). Date of sinpection: 21/08/2008. Date of signature: 04/03/2009.
Type of method:
effusion method: vapour pressure balance

Test material

Constituent 1
Chemical structure
Reference substance name:
4,4'-bis(methoxymethyl)-1,1'-biphenyl
EC Number:
700-008-0
Cas Number:
3753-18-2
Molecular formula:
C16 H18 O2
IUPAC Name:
4,4'-bis(methoxymethyl)-1,1'-biphenyl
Constituent 2
Reference substance name:
4,4-bis(methoxymethyl)-biphenyl
IUPAC Name:
4,4-bis(methoxymethyl)-biphenyl

Results and discussion

Vapour pressure
Temp.:
25 °C
Vapour pressure:
0 Pa
Transition / decomposition
Transition / decomposition:
no

Any other information on results incl. tables

Results

Run1

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

35

308.15

0.003245173

1.03

1.030E-09

0.001429904

-2.844693154

36

309.15

0.003234676

1.24

1.240E-09

0.001721438

-2.764108694

37

310.15

0.003224246

1.75

1.750E-09

0.002429448

-2.614492330

38

311.15

0.003213884

2.27

2.270E-09

0.003151342

-2.501504522

39

312.15

0.003203588

2.78

2.780E-09

0.003859352

-2.413485583

40

313.15

0.003193358

3.50

3.500E-09

0.004858897

-2.313462334

41

314.15

0.003183193

3.91

3.910E-09

0.005428082

-2.265353621

42

315.15

0.003173092

4.63

4.630E-09

0.006427626

-2.191949388

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 1 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -9318.209
Standard deviation in slope     481.838

Intercept                                        27.413
Standard deviation in intercept    1.546

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -9318.209/temp(K) + 27.413

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -3.841.

Run 2

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

36

309.15

0.003234676

1.54

1.540E-09

0.002137915

-2.670009658

37

310.15

0.003224246

1.85

1.850E-09

0.002568274

-2.590358650

38

311.15

0.003213884

2.27

2.270E-09

0.003151342

-2.501504522

39

312.15

0.003203588

2.88

2.880E-09

0.003998178

-2.398137891

40

313.15

0.003193358

3.81

3.810E-09

0.005289256

-2.276605403

41

314.15

0.003183193

4.02

4.020E-09

0.005580790

-2.253304326

42

315.15

0.003173092

4.53

4.530E-09

0.006288801

-2.201432177

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 2 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -8024.254
Standard deviation in slope     552.540

Intercept                                        23.294
Standard deviation in intercept    1.770

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -8024.254/temp(K) + 23.294

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -3.619.

Run 3

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

35

308.15

0.003245173

1.03

1.030E-09

0.001429904

-2.844693154

36

309.15

0.003234676

1.34

1.340E-09

0.001860263

-2.730425580

37

310.15

0.003224246

1.65

1.650E-09

0.002290623

-2.640046435

38

311.15

0.003213884

2.27

2.270E-09

0.003151342

-2.501504522

39

312.15

0.003203588

2.68

2.680E-09

0.003720527

-2.429395585

40

313.15

0.003193358

3.30

3.300E-09

0.004581245

-2.339016439

41

314.15

0.003183193

3.91

3.910E-09

0.005428082

-2.265353621

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 3 gives the following statistical data using an unweighted least squares treatment.

Slope                                       -9447.292
Standard deviation in slope     352.587

Intercept                                        27.828
Standard deviation in intercept    1.133

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -9447.292/temp(K) + 27.828

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -3.858.

Run 4

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

33

306.15

0.003266373

0.51

5.100E-10

0.000708011

-3.149960203

34

307.15

0.003255738

0.72

7.200E-10

0.000999544

-3.000197882

35

308.15

0.003245173

1.03

1.030E-09

0.001429904

-2.844693154

36

309.15

0.003234676

1.54

1.540E-09

0.002137915

-2.670009658

37

310.15

0.003224246

1.85

1.850E-09

0.002568274

-2.590358650

38

311.15

0.003213884

2.37

2.370E-09

0.003290167

-2.482782033

39

312.15

0.003203588

3.09

3.090E-09

0.004289712

-2.367571899

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 4 gives the following statistical data using an unweighted least squares treatment.

Slope                                    -12417.416
Standard deviation in slope     591.114

Intercept                                        37.439
Standard deviation in intercept    1.912

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -12417.416/temp(K) + 37.439

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -4.210.

Run 5

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

33

306.15

0.003266373

0.41

4.100E-10

0.000569185

-3.244746522

34

307.15

0.003255738

0.51

5.100E-10

0.000708011

-3.149960203

35

308.15

0.003245173

0.72

7.200E-10

0.000999544

-3.000197882

36

309.15

0.003234676

1.34

1.340E-09

0.001860263

-2.730425580

37

310.15

0.003224246

1.75

1.750E-09

0.002429448

-2.614492330

38

311.15

0.003213884

2.16

2.160E-09

0.002998633

-2.523076628

39

312.15

0.003203588

2.99

2.990E-09

0.004150886

-2.381859190

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 5 gives the following statistical data using an unweighted least squares treatment.

Slope                                    -14434.604
Standard deviation in slope     886.309

Intercept                                        43.887
Standard deviation in intercept    2.867

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -14434.604/temp(K) + 43.887

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -4.527.

Run 6

Temperature (ºC)

Temperature (K)

Reciprocal Temperature (K-1)

Mass Difference (µg)

Mass Difference (kg)

Vapour Pressure (Pa)

Log10Vp

34

307.15

0.003255738

0.62

6.200E-10

0.000860719

-3.065138689

35

308.15

0.003245173

0.72

7.200E-10

0.000999544

-3.000197882

36

309.15

0.003234676

1.24

1.240E-09

0.001721438

-2.764108694

37

310.15

0.003224246

1.75

1.750E-09

0.002429448

-2.614492330

38

311.15

0.003213884

2.37

2.370E-09

0.003290167

-2.482782033

39

312.15

0.003203588

2.99

2.990E-09

0.004150886

-2.381859190

40

313.15

0.003193358

3.71

3.710E-09

0.005150430

-2.288156469

 

A plot of Log10(vapour pressure (Pa)) versus reciprocal temperature (1/T(K)) for Run 6 gives the following statistical data using an unweighted least squares treatment.

Slope                                    -13227.824
Standard deviation in slope     819.748

Intercept                                        39.995
Standard deviation in intercept    2.643

The results obtained indicate the following vapour pressure relationship:

Log10(Vp (Pa)) = -13227.824/temp(K) + 39.995

The above yields a vapour pressure (Pa) at 298.15 K with a common logarithm of -4.371.

Summary of Results

Run

Log10[Vp(25ºC)]

1

-3.841

2

-3.619

3

-3.858

4

-4.210

5

-4.527

6

-4.371

Mean

-4.071

Vapour Pressure

8.5 x 10-5Pa

The test material did not change in appearance under the conditions used in the determination.


Applicant's summary and conclusion

Conclusions:
The vapour pressure of the test material has been determined to be 8.5 x 10-5 Pa at 25ºC.
Executive summary:

The vapour pressure was determined using a vapour pressure balance with measurements being made at several temperatures and linear regression analysis used to calculate the vapour pressure at 25°C. Testing was conducted using Method A4 Vapour Pressure of Council Regulation (EC) No 440/2208 of 30 May 2008, Part A: Methods for the determination of physico-chemical properties.

The vapour pressure of the test material has been determined to be 8.5 x 10-5Pa at 25ºC.